Salesforce JavaScript Developer Practice Exam 2025 – 400 Free Practice Questions to Pass the Exam

To understand the output of the code, we need to examine how the function `multiply` and the spreading operator work in JavaScript, specifically how the default parameter and object mutability are interacting in this scenario.

Firstly, the `value` object is initialized with a property `number` set to `10`. When the `multiply` function is called without arguments, it uses the spread operator to create a shallow copy of `value`. This means that on the first call of `multiply()`, a new object is created with a `number` property initialized to `10`. Importantly, this new instance is not linked to the original `value` object, allowing it to be modified independently.

On the first call of `multiply()`, the new object's `number` property is multiplied by `2`, resulting in `20`. This value is then logged to the console. The second call of `multiply()` behaves the same way, again creating a new object with `number` set to `10`, and after multiplying it by `2`, it logs `20` again.

On the third call, `multiply(value)` is executed. Here, you are passing the original `value` object. In this instance, the `number` property of